NYCPHP Meetup

[Phil Powell]

I did paste the code, here it is again:

MINE: http://valsignalandet.com/aablah.php

<?php

 function change(&$array, $index) {
  $array =  strtoupper($array);
}

$blah = array('a', 'b', 'c');
var_dump($blah);
array_walk($blah, 'change');
var_dump($blah);

?>


YOURS: http://valsignalandet.com/aablah2.php

<?php
 $arr = array('a', 'b', 'c');
 var_dump($arr);
 function change(&$array, $index) {
 $array = 'I have changed you!';
 }

 array_walk($arr, 'change');
 var_dump($arr);
 ?>

Environment: PHP 4.1.3 UNIX/Apache

Phil

----- Original Message ----- 
From: "Daniel Kushner" <nyphp at websapp.com>
To: "NYPHP Talk" <talk at lists.nyphp.org>
Sent: Thursday, November 06, 2003 10:53 PM
Subject: RE: [nycphp-talk] Second time array_walk failed for me


> Can you paste the code that you're testing?
>
> > -----Original Message-----
> > From: talk-bounces at lists.nyphp.org
> > [mailto:talk-bounces at lists.nyphp.org]On Behalf Of Phil Powell
> > Sent: Thursday, November 06, 2003 10:46 PM
> > To: NYPHP Talk
> > Subject: Re: [nycphp-talk] Second time array_walk failed for me
> >
> >
> > Ok, Daniel, let's investigate here:
> >
> > 1) what version of PHP are you using? I am using 4.1.3
> >
> > 2) Why does your work, here is mine and it does NOT work!
> >
> > <?php
> >
> >  function change(&$array, $index) {
> >   $array =  strtoupper($array);
> > }
> >
> > $blah = array('a', 'b', 'c');
> > var_dump($blah);
> > array_walk($blah, 'change');
> > var_dump($blah);
> >
> > ?>
> >
> > Go to http://valsignalandet.com/aablah.php and see the results..
> > It does NOT
> > work!!!
> >
> > However, yours does (go to http://valsignalandet.com/aablah2.php) Here
is
> > the code I copied:
> >
> >  <?php
> >  $arr = array('a', 'b', 'c');
> >  var_dump($arr);
> >  function change(&$array, $index) {
> >  $array = 'I have changed you!';
> >  }
> >
> >  array_walk($arr, 'change');
> >  var_dump($arr);
> >  ?>
> >
> >
> > Why does yours work and mine does not, exact same logic only different
> > methodology, one returns a result, the other does not..  That is
> > not enough
> > proof to just say "Good job PHP Team" and declare array_walk saves the
> > universe from eternal peril.
> >
> > Phil
> > ----- Original Message -----
> > From: "Daniel Kushner" <nyphp at websapp.com>
> > To: "NYPHP Talk" <talk at lists.nyphp.org>
> > Sent: Thursday, November 06, 2003 10:18 PM
> > Subject: RE: [nycphp-talk] Second time array_walk failed for me
> >
> >
> > > Phil,
> > >
> > > >
> > > > 1) Why does the PHP manual say that "array_walk" CAN change the
values
> > in
> > > > the array, when, in fact, it can't?
> > >
> > > yes it can!
> > >
> > > > 2) If 1 is answerable, does that mean the manual is either
> > misleading on
> > > > array_walk, or, oh no WRONG?
> > >
> > > >From the manual:
> > > Note: If function needs to be working with the actual values of
> > the array,
> > > specify the first parameter of function as a reference. Then,
> > any changes
> > > made to those elements will be made in the original array itself.
> > >
> > >
> > > Some code to test:
> > > <?php
> > > $arr = array('a', 'b', 'c');
> > > var_dump($arr);
> > > function change(&$array, $index) {
> > > $array = 'I have changed you!';
> > > }
> > >
> > > array_walk($arr, 'change');
> > > var_dump($arr);
> > > ?>
> > >
> > > The output:
> > > array(3) { [0]=> string(1) "a" [1]=> string(1) "b" [2]=> string(1)
"c" }
> > >
> > > array(3) { [0]=> string(19) "I have changed you!" [1]=>
> > string(19) "I have
> > > changed you!" [2]=> string(19) "I have changed you!" }
> > >
> > >
> > >
> > > Oh my, it works !! Great job PHP Team !
> > >
> > > --Daniel
> > >
> > >
> > > _______________________________________________
> > > talk mailing list
> > > talk at lists.nyphp.org
> > > http://lists.nyphp.org/mailman/listinfo/talk
> >
> > _______________________________________________
> > talk mailing list
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>
>
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